If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2-4X-11=-5
We move all terms to the left:
X^2-4X-11-(-5)=0
We add all the numbers together, and all the variables
X^2-4X-6=0
a = 1; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·1·(-6)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{10}}{2*1}=\frac{4-2\sqrt{10}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{10}}{2*1}=\frac{4+2\sqrt{10}}{2} $
| X^2-6x+4=-3 | | 5^n-99/5=0 | | R^2-6r+4=-3 | | 0.2(x-4)+0.5=1-0.1(8-2x)-0.5 | | R^2-6r+12=3 | | K^2-k+2=2 | | f=23(4f-1) | | 10+x=70-x | | 3x^2+3x-21=-3 | | 3x^2+3=12 | | x×2+21=15 | | c=305+50 | | 2a^2-3=-1 | | x^2+2x=0 | | 3p^2-1=8 | | -2j+-5=-15 | | 3x^2-2=22 | | 5y–(11–2y)=3 | | 0=-9,82*x+16*0,3420201 | | 32.8=(12)x+7 | | 8÷2x-3=4 | | x-(x+1)+(x-2)=69, | | 3.6^x=6 | | 9-4x=36 | | 5x-(2x+2)=88 | | 34=-2+9x+16+1x | | 6g−3g=15 | | 5x+(x+2)=92, | | u/5+3=18 | | 9y+3=16y+15 | | y+4/12-y-1/12=y/2 | | 9x+2=11x-20 |